(x)=5x^2-20x+3

Solution for (x)=5x^2-20x+3 equation:

(x)=5x^2-20x+3

We move all terms to the left:

(x)-(5x^2-20x+3)=0

We get rid of parentheses

-5x^2+x+20x-3=0

We add all the numbers together, and all the variables

-5x^2+21x-3=0

a = -5; b = 21; c = -3;
Δ = b2-4ac
Δ = 212-4·(-5)·(-3)
Δ = 381
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{381}}{2*-5}=\frac{-21-\sqrt{381}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{381}}{2*-5}=\frac{-21+\sqrt{381}}{-10}
$